1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
|
#!/usr/bin/pytnon2
## You are given a list of "pegs" with their location (positive integers, asc order).
## these pegs can accept gears with radius > 1
## the goal is the last gear to be spinning twice as fast as the 1st one for any given list
## if it's possible return the first gear's radius in a list [a,b] where the ratio is a/b
## if not return [-1,-1]
from fractions import gcd
from functools import reduce
# test
from random import seed
from random import random
def simplify(ratio_nums):
return list(map(reduce(gcd, ratio_nums).__rfloordiv__, ratio_nums))
def solution(pegs):
if len(pegs) == 2:
r1_by_three = 2 * (pegs[1] - pegs[0])
nums = [r1_by_three, 3]
return simplify(nums)
S = pegs[-1] - pegs[0]
if len(pegs) % 2 == 0:
C = 0
for i in range (1, len(pegs) - 1):
C += (-1)**i * pegs[i]
r1_by_three = 2 * S - 4 * C
r = [r1_by_three/3]
for i in range(len(pegs) -1):
r.append(pegs[i+1]-pegs[i]-r[i])
if r[-1] < 1:
return [-1, -1]
if (r[0]) < 1 or (r[0]) > pegs[1]-pegs[0]-1:
return [-1, -1]
return simplify([r1_by_three, 3])
else:
K = 0
for i in range (1, len(pegs) - 2):
K += (-1)**i * pegs[i]
r1 = 2*S - 4*K - 4*pegs[-1] + 4*pegs[-2]
if r1 < 1:
return [-1, -1]
return [r1, 1]
seed(1)
def ran():
return int(random() * 1000)
for i in range(1,1000):
a=[ran(),ran(),ran(),ran(),ran(),ran()]
a.sort()
print(a)
print(solution(a))
print("")
|
